Consider the function defined below.
struct item {
int data;
struct item * next;
};
int f(struct item *p) {
return ((p == NULL) || (p->next == NULL)||
((p->data <= p ->next -> data) &&
f(p->next)));
}
For a given linked list , the function returns if and only if
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Answer: B
Let us analyze the behavior of the recursive function :
- Base Cases:
p == NULL: If the list is empty, the function immediately returns1(true).p->next == NULL: If the list has exactly one element, the function immediately returns1(true).
- Recursive Step:
If the list has two or more elements, the function returns
1if and only if:(p->data <= p->next->data) && f(p->next)is true.This condition requires that:
- The current element's data is less than or equal to the next element's data ().
- The remaining sublist starting from
p->nextis also recursively verified to satisfy the same condition.
Combining these conditions, the function returns 1 if and only if every element in the list is less than or equal to its succeeding element. This is the definition of a list sorted in non-decreasing order.
Therefore, the correct option is B.
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