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Official PYQ · 2015

GATE CS 2015 Set 3 Q44 — Boolean Algebra

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Given the function F=P′+QRF = P' +QR, where FF is a function in three Boolean variables P,QP, Q and RR and P′=!PP'=!P, consider the following statements.

(S1)F=∑(4,5,6)(S1) F = \sum(4, 5, 6)

(S2)F=∑(0,1,2,3,7)(S2) F = \sum(0, 1, 2, 3, 7)

(S3)F=Π(4,5,6)(S3) F = \Pi (4, 5, 6)

(S4)F=Π(0,1,2,3,7)(S4) F = \Pi (0, 1, 2, 3, 7)

Which of the following is true?

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Answer: A

To determine which statements are true, we need to find both the canonical Sum of Products (SOP) and Product of Sums (POS) representations of the Boolean function F(P,Q,R)=P′+QRF(P, Q, R) = P' + QR.

1. Finding the Minterms (SOP Form)

We expand each term of FF to include all three variables P,Q,P, Q, and RR:

  • Term P′P': P′=P′(Q+Q′)(R+R′)=P′(QR+QR′+Q′R+Q′R′)=P′QR+P′QR′+P′Q′R+P′Q′R′\begin{aligned} P' &= P'(Q + Q')(R + R') \\ &= P'(QR + QR' + Q'R + Q'R') \\ &= P'QR + P'QR' + P'Q'R + P'Q'R' \end{aligned} These correspond to minterms m3 (0112)m_3\ (011_2), m2 (0102)m_2\ (010_2), m1 (0012)m_1\ (001_2), and m0 (0002)m_0\ (000_2).
  • Term QRQR: QR=(P+P′)QR=PQR+P′QR\begin{aligned} QR &= (P + P')QR \\ &= PQR + P'QR \end{aligned} These correspond to minterms m7 (1112)m_7\ (111_2) and m3 (0112)m_3\ (011_2).

Combining the unique minterms, we get:

F(P,Q,R)=∑(0,1,2,3,7)F(P, Q, R) = \sum(0, 1, 2, 3, 7)

This tells us:

  • (S1) F=∑(4,5,6)F = \sum(4, 5, 6) is False.
  • (S2) F=∑(0,1,2,3,7)F = \sum(0, 1, 2, 3, 7) is True.

2. Finding the Maxterms (POS Form)

The maxterms of a function are the indices that are not present in its minterm list. Since the minterms are {0,1,2,3,7}\{0, 1, 2, 3, 7\}, the remaining indices from the set {0,1,2,3,4,5,6,7}\{0, 1, 2, 3, 4, 5, 6, 7\} are {4,5,6}\{4, 5, 6\}.

Thus, the POS representation is:

F(P,Q,R)=Π(4,5,6)F(P, Q, R) = \Pi(4, 5, 6)

This tells us:

  • (S3) F=Π(4,5,6)F = \Pi(4, 5, 6) is True.
  • (S4) F=Π(0,1,2,3,7)F = \Pi(0, 1, 2, 3, 7) is False.

Conclusion

The statements evaluate to:

  • (S1)-False, (S2)-True, (S3)-True, (S4)-False

This matches Option A.

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