Answer: 0.75
We are given that X1,X2,X3 are independent and identically distributed (i.i.d.) random variables with:
Pr[Xi=0]=Pr[Xi=1]=21for i=1,2,3
We need to find the conditional probability Pr[Y=0∣X3=0], where Y=X1X2⊕X3.
Given the condition X3=0, we can substitute X3=0 into the expression for Y:
Y=X1X2⊕0=X1X2
Since X3 is independent of X1 and X2, the conditional probability simplifies to:
Pr[Y=0∣X3=0]=Pr[X1X2=0]
The product X1X2=0 if and only if at least one of X1 or X2 is 0. Thus:
Pr[X1X2=0]=1−Pr[X1X2=1]
Since X1 and X2 are independent:
Pr[X1X2=1]=Pr[X1=1]⋅Pr[X2=1]=21×21=0.25
Therefore:
Pr[Y=0∣X3=0]=1−0.25=0.75