Let and be regular sets defined over the alphabet Then:
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Answer: B;C
Regular languages (or regular sets) are closed under standard boolean and algebraic operations. Let's analyze each option based on these closure properties:
- Option A: is not regular.
Incorrect. Regular languages are closed under intersection. If and are regular, then is guaranteed to be regular. - Option B: is regular.
Correct. Regular languages are closed under union. If and are regular, then is regular. - Option C: is regular.
Correct. The set represents the complement of (often written as ). Since regular languages are closed under complementation, is regular. - Option D: is not regular.
Incorrect. Regular languages are closed under the Kleene star operation. If is regular, then is also regular.
Thus, the correct statements are B and C.
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