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Official PYQ · 2002

GATE CS 2002 Q1.14 — Number Representations (Fixed and Floating Point)

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The decimal value 0.250.25

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Answer: B

To convert the decimal fraction 0.250.25 to its binary equivalent, we can express it as a sum of powers of 22:

0.25=14=122=2−20.25 = \frac{1}{4} = \frac{1}{2^2} = 2^{-2}

In the binary positional number system, the positions to the right of the radix point represent negative powers of 22:

(0.b1b2b3… )2=b1×2−1+b2×2−2+b3×2−3+…(0.b_1 b_2 b_3 \dots)_2 = b_1 \times 2^{-1} + b_2 \times 2^{-2} + b_3 \times 2^{-3} + \dots

Comparing this with our value 2−22^{-2}:

  • b1=0b_1 = 0 (since there is no 2−12^{-1} term)
  • b2=1b_2 = 1 (since we have 1×2−21 \times 2^{-2})
  • b3=b4=⋯=0b_3 = b_4 = \dots = 0

Thus, the binary representation of 0.250.25 is (0.01)2(0.01)_2.

Therefore, the correct option is B.

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