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Official PYQ · 1987

GATE CS 1987 Q1-xxvi — Maxima and Minima, Mean Value Theorem, Integration

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If f(xi).f(xi+1)<0f(x_{i}).f(x_{i+1})< 0 then

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Answer: A

Under the standard assumption that f(x)f(x) is a continuous function on the interval [xi,xi+1][x_i, x_{i+1}], we can apply the Intermediate Value Theorem (IVT).

The Intermediate Value Theorem states that if a function f(x)f(x) is continuous on a closed interval [a,b][a, b], and uu is any value between f(a)f(a) and f(b)f(b), then there exists at least one c∈(a,b)c \in (a, b) such that f(c)=uf(c) = u.

Given that f(xi)⋅f(xi+1)<0f(x_i) \cdot f(x_{i+1}) < 0, the function values at the endpoints have opposite signs (one is positive and the other is negative). Since 00 lies strictly between these two values, there must exist at least one root c∈(xi,xi+1)c \in (x_i, x_{i+1}) such that:

f(c)=0f(c) = 0

Thus, there must be a root of f(x)f(x) between xix_i and xi+1x_{i+1}. This principle forms the basis of root-finding algorithms like the Bisection Method.

Options C and D are incorrect because the signs of the function values at the endpoints do not provide any information about the vanishing of the fourth derivative.

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