Consider two decision problems such that reduces in polynomial time to 3-SAT and 3-SAT reduces in polynomial time to . Then which one of the following is consistent with the above statement?
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Answer: A
We are given two polynomial-time reductions:
- : Since is in and the class is closed under polynomial-time reductions, any decision problem that reduces to a problem in must also be in . Thus, .
- : Since is an -complete (and hence -hard) problem, reducing it to in polynomial time establishes that is at least as hard as . Thus, is -hard.
Therefore, is in and is -hard, which is consistent with Option A.
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