Answer: A
We are given two equivalences:
- a⟺(b∨¬b)
Since b∨¬b is a tautology (always True), the proposition a must always be True (a≡True).
- b⟺c
This means b and c always have the same truth value (b≡c).
Now, let us evaluate the given formula:
ϕ=(a∧b)→(a∧c)∨d
Substituting a≡True into the formula:
ϕ≡(True∧b)→(True∧c)∨d
ϕ≡b→(c∨d)
Since b≡c, we can substitute c with b:
ϕ≡b→(b∨d)
Using the implication identity P→Q≡¬P∨Q:
ϕ≡¬b∨(b∨d)
ϕ≡(¬b∨b)∨d
Since ¬b∨b≡True:
ϕ≡True∨d≡True
Thus, the truth-value of the formula is always True.