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GATE CS 1992 Q01 — Data Link Layer: Framing, Error Detection, MAC, Ethernet Bridging

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Consider a 33-bit error detection and 11-bit error correction hamming code for 44-bit data. The extra parity bits required would be _____ and the 33-bit error detection is possible because the code has a minimum distance of _______.
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Answer: 3 : 4

To find the required values, we break the problem into two parts:

  1. Number of extra parity bits (rr):
    For a Hamming code to correct 11-bit errors, the number of parity bits rr for mm data bits must satisfy the Hamming rule:2r≥m+r+12^r \ge m + r + 1Given m=4m = 4 data bits:2r≥4+r+1  ⟹  2r≥r+52^r \ge 4 + r + 1 \implies 2^r \ge r + 5Testing values of rr:
    • For r=2r = 2: 22=4≱72^2 = 4 \not\ge 7
    • For r=3r = 3: 23=8≥82^3 = 8 \ge 8 (Satisfied)
    Thus, the number of extra parity bits required is 3.
  2. Minimum Hamming distance (dmind_{\text{min}}) for error detection:
    To detect up to tt errors, the minimum Hamming distance of the code must satisfy:dmin≥t+1d_{\text{min}} \ge t + 1For 33-bit error detection (t=3t = 3):dmin≥3+1=4d_{\text{min}} \ge 3 + 1 = 4Thus, the minimum distance required is 4.

Therefore, the blanks are filled with 3 and 4 respectively (represented as 3 : 4).

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