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Official PYQ · 2024

GATE CS 2024 Set 2 Q5 — General Aptitude

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​​​​​In the sequence 6,9,14,x,30,416,9,14, x, 30,41, a possible value of xx is

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Answer: B

Let us analyze the differences between consecutive terms of the given sequence: 6,9,14,x,30,416, 9, 14, x, 30, 41.

Let the differences between consecutive terms be denoted as d1,d2,d3,d4,d5d_1, d_2, d_3, d_4, d_5:

  • d1=9−6=3d_1 = 9 - 6 = 3
  • d2=14−9=5d_2 = 14 - 9 = 5
  • d3=x−14d_3 = x - 14
  • d4=30−xd_4 = 30 - x
  • d5=41−30=11d_5 = 41 - 30 = 11

The known differences are 3,5,…,…,113, 5, \dots, \dots, 11. This sequence of differences represents consecutive odd numbers starting from 33:

3,5,7,9,113, 5, 7, 9, 11

Applying this pattern, we find xx by adding the next odd number (77) to the third term:

x=14+7=21x = 14 + 7 = 21

We can verify this value with the subsequent term:

30−x=30−21=930 - x = 30 - 21 = 9

Since 99 is indeed the next consecutive odd number, the pattern is consistent. Thus, the value of xx is 2121.

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