Answer: B;C
We are given the following probabilities for events A and B:
- P(A)=0.3
- P(B)=0.5
- P(A∩B)=0.1
Let's evaluate each option step-by-step:
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The two events A and B are independent:
Two events A and B are independent if and only if P(A∩B)=P(A)⋅P(B).
P(A)⋅P(B)=0.3×0.5=0.15
Since P(A∩B)=0.1=0.15, the events A and B are not independent. Thus, statement A is FALSE.
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P(A∪B)=0.7:
Using the addition rule of probability:
P(A∪B)=P(A)+P(B)−P(A∩B)
P(A∪B)=0.3+0.5−0.1=0.7
Thus, statement B is TRUE.
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P(A∩Bc)=0.2:
The probability of event A occurring but not B is given by:
P(A∩Bc)=P(A)−P(A∩B)
P(A∩Bc)=0.3−0.1=0.2
Thus, statement C is TRUE.
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P(Ac∩Bc)=0.4:
Using De Morgan's Law:
P(Ac∩Bc)=P((A∪B)c)=1−P(A∪B)
P(Ac∩Bc)=1−0.7=0.3
Since 0.3=0.4, statement D is FALSE.