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Official PYQ · 2024

GATE CS 2024 Set 1 Q17 — Probability: Random Variables and Distributions

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Let AA and BB be two events in a probability space with P(A)=0.3,P(B)=0.5P(A)=0.3, P(B)=0.5, and P(A∩B)=0.1P(A \cap B)=0.1. Which of the following statements is/are TRUE?

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Answer: B;C

We are given the following probabilities for events AA and BB:

  • P(A)=0.3P(A) = 0.3
  • P(B)=0.5P(B) = 0.5
  • P(A∩B)=0.1P(A \cap B) = 0.1

Let's evaluate each option step-by-step:

  1. The two events AA and BB are independent:

    Two events AA and BB are independent if and only if P(A∩B)=P(A)⋅P(B)P(A \cap B) = P(A) \cdot P(B).

    P(A)⋅P(B)=0.3×0.5=0.15P(A) \cdot P(B) = 0.3 \times 0.5 = 0.15

    Since P(A∩B)=0.1≠0.15P(A \cap B) = 0.1 \neq 0.15, the events AA and BB are not independent. Thus, statement A is FALSE.

  2. P(A∪B)=0.7P(A \cup B) = 0.7:

    Using the addition rule of probability:

    P(A∪B)=P(A)+P(B)−P(A∩B)P(A \cup B) = P(A) + P(B) - P(A \cap B)

    P(A∪B)=0.3+0.5−0.1=0.7P(A \cup B) = 0.3 + 0.5 - 0.1 = 0.7

    Thus, statement B is TRUE.

  3. P(A∩Bc)=0.2P(A \cap B^c) = 0.2:

    The probability of event AA occurring but not BB is given by:

    P(A∩Bc)=P(A)−P(A∩B)P(A \cap B^c) = P(A) - P(A \cap B)

    P(A∩Bc)=0.3−0.1=0.2P(A \cap B^c) = 0.3 - 0.1 = 0.2

    Thus, statement C is TRUE.

  4. P(Ac∩Bc)=0.4P(A^c \cap B^c) = 0.4:

    Using De Morgan's Law:

    P(Ac∩Bc)=P((A∪B)c)=1−P(A∪B)P(A^c \cap B^c) = P((A \cup B)^c) = 1 - P(A \cup B)

    P(Ac∩Bc)=1−0.7=0.3P(A^c \cap B^c) = 1 - 0.7 = 0.3

    Since 0.3≠0.40.3 \neq 0.4, statement D is FALSE.

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