Answer: A
The recurrence relation is given by Ln=Ln−1+Ln−2 for n≥3 with L1=1 and L2=3.
The characteristic equation of this recurrence relation is:
r2−r−1=0
The roots of this equation are:
r1=21+5andr2=21−5
The general solution is of the form Ln=c1r1n+c2r2n. We can find the correct option by testing the base cases n=1 and n=2 for Option A:
- For n=1:
L1=(21+5)1+(21−5)1=21+5+1−5=1
- For n=2:
L2=(21+5)2+(21−5)2=46+25+46−25=412=3
Since both initial conditions are satisfied, Option A is the correct closed-form expression.