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Official PYQ · 2016

GATE CS 2016 Set 1 Q06 — Boolean Algebra

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Consider the Boolean operator # with the following properties :

x#0=x,x#1=x‾,x#x=0x \# 0 = x, x \# 1=\overline{x}, x \# x = 0 and x#x‾=1.x \# \overline{x} = 1. Then x#yx\#y is equivalent to 

Choose one option
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Answer: A

The given properties of the operator #\# are:

  • x#0=xx \# 0 = x
  • x#1=x‾x \# 1 = \overline{x}
  • x#x=0x \# x = 0
  • x#x‾=1x \# \overline{x} = 1

These properties uniquely define the Exclusive-OR (XOR) operation, denoted by ⊕\oplus:

  • x⊕0=xx \oplus 0 = x
  • x⊕1=x‾x \oplus 1 = \overline{x}
  • x⊕x=0x \oplus x = 0
  • x⊕x‾=1x \oplus \overline{x} = 1

Therefore, x#y=x⊕y=xy‾+x‾yx \# y = x \oplus y = x\overline{y} + \overline{x}y.

Thus, the correct option is A.

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