Answer: 9
Any polynomial f(x) can be uniquely decomposed into its even part P(x) and odd part Q(x):
f(x)=P(x)+Q(x)
where P(x)=2f(x)+f(−x) is an even polynomial, and Q(x)=2f(x)−f(−x) is an odd polynomial.
We are given that the degree of f(x)+f(−x) is 10. Since f(x)+f(−x)=2P(x), the degree of the even polynomial P(x) is 10.
Now, let us find the derivative g(x)=f′(x):
g(x)=P′(x)+Q′(x)
Using the properties of derivatives of even and odd functions:
- Since P(x) is even, its derivative P′(x) is an odd function, meaning P′(−x)=−P′(x).
- Since Q(x) is odd, its derivative Q′(x) is an even function, meaning Q′(−x)=Q′(x).
Thus, we can compute g(x)−g(−x) as follows:
g(x)−g(−x)=(P′(x)+Q′(x))−(P′(−x)+Q′(−x))=(P′(x)+Q′(x))−(−P′(x)+Q′(x))=2P′(x)
Since P(x) is a polynomial of degree 10, its derivative P′(x) is a polynomial of degree 10−1=9. Therefore, the degree of g(x)−g(−x) is 9.