GATE CS 2016 Set 2 QGA-04 — General Aptitude

To find the odd one out, let us analyze the alphabetical positions of the letters in each option:

1. CADBE
   • Positions: $\text{C}(3) \to \text{A}(1) \to \text{D}(4) \to \text{B}(2) \to \text{E}(5)$
   • Pattern of differences: $-2, +3, -2, +3$
2. JHKIL
   • Positions: $\text{J}(10) \to \text{H}(8) \to \text{K}(11) \to \text{I}(9) \to \text{L}(12)$
   • Pattern of differences: $-2, +3, -2, +3$
3. XVYWZ
   • Positions: $\text{X}(24) \to \text{V}(22) \to \text{Y}(25) \to \text{W}(23) \to \text{Z}(26)$
   • Pattern of differences: $-2, +3, -2, +3$
4. ONPMQ
   • Positions: $\text{O}(15) \to \text{N}(14) \to \text{P}(16) \to \text{M}(13) \to \text{Q}(17)$
   • Pattern of differences: $-1, +2, -3, +4$

Options A, B, and C all follow the identical pattern of differences: $-2, +3, -2, +3$. Option D does not follow this pattern, making it the odd one out.