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Official PYQ · 2021

GATE CS 2021 Set 2 Q15 — Propositional and First Order Logic

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Choose the correct choice(s) regarding the following proportional logic assertion SS:

S:((P∧Q)→R)→((P∧Q)→(Q→R))S: (( P \wedge Q) \rightarrow R) \rightarrow (( P \wedge Q) \rightarrow (Q \rightarrow R))

Select all correct options
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Answer: B;D

To determine the nature of the propositional logic assertion SS, let us analyze its antecedent and consequent separately.

Let the assertion be S:A→CS: A \rightarrow C, where:

  • Antecedent (AA): (P∧Q)→R(P \wedge Q) \rightarrow R
  • Consequent (CC): (P∧Q)→(Q→R)(P \wedge Q) \rightarrow (Q \rightarrow R)

Step 1: Simplify the Consequent (CC)

Using the implication equivalence X→Y≡¬X∨YX \rightarrow Y \equiv \neg X \vee Y, we can rewrite CC as:

C≡¬(P∧Q)∨(Q→R)C \equiv \neg(P \wedge Q) \vee (Q \rightarrow R)

Applying De Morgan's Law and rewriting the inner implication:

C≡(¬P∨¬Q)∨(¬Q∨R)C \equiv (\neg P \vee \neg Q) \vee (\neg Q \vee R)

By associativity and idempotency of disjunction (¬Q∨¬Q≡¬Q\neg Q \vee \neg Q \equiv \neg Q):

C≡¬P∨¬Q∨RC \equiv \neg P \vee \neg Q \vee R

Applying De Morgan's Law again to group ¬P∨¬Q\neg P \vee \neg Q:

C≡¬(P∧Q)∨RC \equiv \neg(P \wedge Q) \vee R

Converting back to implication form:

C≡(P∧Q)→RC \equiv (P \wedge Q) \rightarrow R

Step 2: Compare Antecedent and Consequent

We observe that:

C≡AC \equiv A

Thus, the antecedent of SS is logically equivalent to the consequent of SS. This makes Option D correct.

Step 3: Analyze the Assertion SS

Since A≡CA \equiv C, the assertion SS can be written as:

S:A→AS: A \rightarrow A

An implication where the hypothesis and conclusion are logically equivalent is always true (a tautology). Thus, SS is a tautology, making Option B correct.

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