Consider the cyclic redundancy check based error detecting scheme having the generator polynomial . Suppose the message is to be transmitted. Check bits are appended at the end of the message by the transmitter using the above scheme. The transmitted bit string is denoted by . The value of the checkbit sequence is
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Answer: C
To find the CRC check bits , we perform modulo-2 division of the appended message by the generator polynomial.
Step 1: Represent the Generator Polynomial in Binary
The generator polynomial is given by: In binary, this corresponds to the divisor: (degree ).
Step 2: Append Zeros to the Message
The message is . Since the degree of the generator polynomial is , we append zeros to the message:
Step 3: Perform Modulo-2 Division
We divide by using modulo-2 division (XOR operation):
111100 (Quotient)
-----------
1011 | 11000000
1011
----
1110
1011
----
1010
1011
----
0010
0000
----
0100
0000
----
100 (Remainder)
The remainder of the division is .
Conclusion
The check bits are the remainder, which is .
Thus, the correct option is C.
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