Let be a group of order , and be a subgroup of such that . Which one of the following options is correct?
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Answer: B
To determine the cyclicity of the group and its subgroup , we analyze their properties based on group theory principles:
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Cyclicity of :
The order of the group is . Up to isomorphism, there are only two groups of order :
- The cyclic group (which is cyclic).
- The symmetric group (which is non-abelian and therefore not cyclic).
Since can be isomorphic to , may not be cyclic.
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Cyclicity of :
By Lagrange's theorem, the order of any subgroup must divide the order of the group . Thus, must be a divisor of .
We are given that . The only divisors of in this range are and .
Since both and are prime numbers, and any group of prime order is always cyclic, must be cyclic.
Therefore, may not be cyclic, but is always cyclic.
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