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Official PYQ · 1996

GATE CS 1996 Q1.5 — Probability: Random Variables and Distributions

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Two dice are thrown simultaneously. The probability that at least one of them will have 66 facing up is

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Answer: D

When two fair dice are thrown simultaneously, the total number of possible outcomes in the sample space SS is:

∣S∣=6×6=36|S| = 6 \times 6 = 36

We want to find the probability of the event EE that at least one of the dice shows a 66.

Method 1: Using the Complement

The complement of "at least one 66" is "no 66 on either die".

  • The probability of not getting a 66 on the first die is 56\frac{5}{6}.
  • The probability of not getting a 66 on the second die is 56\frac{5}{6}.

Since the two rolls are independent, the probability of getting no 66 on both dice is:

P(No 6)=56×56=2536P(\text{No } 6) = \frac{5}{6} \times \frac{5}{6} = \frac{25}{36}

Therefore, the probability of getting at least one 66 is:

P(E)=1−P(No 6)=1−2536=1136P(E) = 1 - P(\text{No } 6) = 1 - \frac{25}{36} = \frac{11}{36}

Method 2: Direct Counting

The favorable outcomes where at least one die shows a 66 are:

{(1,6),(2,6),(3,6),(4,6),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}\{(1, 6), (2, 6), (3, 6), (4, 6), (5, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)\}

Counting these outcomes gives exactly 1111 favorable outcomes.

P(E)=1136P(E) = \frac{11}{36}

Thus, the correct option is D.

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