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Official PYQ · 2010

GATE CS 2010 Q61 — General Aptitude

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If 137+276=435137 + 276 = 435 how much is 731+672?731+672?

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Answer: C

The given addition 137+276=435137 + 276 = 435 is performed in a non-decimal number system with base rr.

To find the base rr, we convert the numbers into their decimal equivalents:

(1⋅r2+3⋅r+7)+(2⋅r2+7⋅r+6)=4⋅r2+3⋅r+5(1 \cdot r^2 + 3 \cdot r + 7) + (2 \cdot r^2 + 7 \cdot r + 6) = 4 \cdot r^2 + 3 \cdot r + 5

Simplifying both sides:

3r2+10r+13=4r2+3r+53r^2 + 10r + 13 = 4r^2 + 3r + 5 r2−7r−8=0r^2 - 7r - 8 = 0 (r−8)(r+1)=0(r - 8)(r + 1) = 0

Since the base rr must be a positive integer, we have r=8r = 8 (octal system).


Now, we perform the addition 7318+6728731_8 + 672_8 in base 8:

  • Units place: 1+2=31 + 2 = 3 (no carry)
  • Eights place: 3+7=10=1×8+2  ⟹  23 + 7 = 10 = 1 \times 8 + 2 \implies 2 with a carry of 11
  • Sixty-fours place: 7+6+1 (carry)=14=1×8+6  ⟹  67 + 6 + 1 \text{ (carry)} = 14 = 1 \times 8 + 6 \implies 6 with a carry of 11
  • Next place: 11 (from carry)

Putting it all together:

7318+6728=16238731_8 + 672_8 = 1623_8

Thus, the correct option is C.

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