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Official PYQ · 1997

GATE CS 1997 Q2-1 — Boolean Algebra

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Let ∗* be defined as x∗y=xˉ+yx * y = \bar{x} + y. Let z=x∗yz = x * y. Value of z∗xz * x is 

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Answer: B

Given the binary operator ∗* defined as:

x∗y=xˉ+yx * y = \bar{x} + y

We are given that z=x∗y=xˉ+yz = x * y = \bar{x} + y. We need to find the value of z∗xz * x.

Applying the definition of the ∗* operator to z∗xz * x:

z∗x=zˉ+xz * x = \bar{z} + x

First, let's find the complement of zz using De Morgan's laws:

zˉ=xˉ+y‾=xˉ‾⋅yˉ=xyˉ\bar{z} = \overline{\bar{x} + y} = \overline{\bar{x}} \cdot \bar{y} = x\bar{y}

Now, substitute zˉ\bar{z} back into the expression for z∗xz * x:

z∗x=(xyˉ)+xz * x = (x\bar{y}) + x

Using the absorption law of Boolean algebra (A+AB=AA + AB = A):

xyˉ+x=x(1+yˉ)=x⋅1=xx\bar{y} + x = x(1 + \bar{y}) = x \cdot 1 = x

Thus, z∗x=xz * x = x, which corresponds to option B.

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