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Official PYQ · 2013

GATE CS 2013 Q26 — Graphs: Connectivity, Matching, Colouring

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The line graph L(G)L(G) of a simple graph GG is defined as follows:

  • There is exactly one vertex v(e)v(e) in L(G)L(G) for each edge ee in GG.
  • For any two edges ee and e′e' in GG, L(G)L(G) has an edge between v(e)v(e) and v(e′)v(e'), if and only if ee and e′e' are incident with the same vertex in GG.

Which of the following statements is/are TRUE?

  • (P) The line graph of a cycle is a cycle.
  • (Q) The line graph of a clique is a clique.
  • (R) The line graph of a planar graph is planar.
  • (S) The line graph of a tree is a tree.
     
Choose one option
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Answer: A

To determine which statements are true, let us analyze each one with definitions and counterexamples:

  • Statement (P): The line graph of a cycle is a cycle.
    Let G=CnG = C_n (n≥3n \ge 3) be a cycle. Each edge in CnC_n is incident to exactly two other edges (one at each endpoint). In the line graph L(Cn)L(C_n), each vertex represents an edge of CnC_n and has a degree of exactly 22. Since CnC_n is connected, L(Cn)L(C_n) is also connected and forms a cycle of length nn (L(Cn)≅CnL(C_n) \cong C_n).
    Thus, (P) is TRUE.

  • Statement (Q): The line graph of a clique is a clique.
    Let G=K4G = K_4 (a clique of size 4). Consider two independent (disjoint) edges in K4K_4, such as e1=(1,2)e_1 = (1, 2) and e2=(3,4)e_2 = (3, 4). Since e1e_1 and e2e_2 do not share any vertex, their corresponding vertices in L(K4)L(K_4) are not connected by an edge. Thus, L(K4)L(K_4) is not a complete graph (clique).
    Thus, (Q) is FALSE.

  • Statement (R): The line graph of a planar graph is planar.
    Let G=K1,5G = K_{1,5} (a star graph with 55 leaves), which is a tree and therefore planar. All 55 edges of K1,5K_{1,5} share the single central vertex, meaning every pair of edges is mutually incident. Consequently, the line graph L(K1,5)L(K_{1,5}) is the complete graph K5K_5. By Kuratowski's Theorem, K5K_5 is non-planar.
    Thus, (R) is FALSE.

  • Statement (S): The line graph of a tree is a tree.
    Let G=K1,3G = K_{1,3} (a star graph with 33 leaves), which is a tree. Since all 33 edges share the central vertex, they are mutually incident. The line graph L(K1,3)L(K_{1,3}) is K3K_3 (a cycle of length 3), which contains a cycle and is therefore not a tree.
    Thus, (S) is FALSE.

Therefore, only statement P is TRUE.

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