The line graph of a simple graph is defined as follows:
- There is exactly one vertex in for each edge in .
- For any two edges and in , has an edge between and , if and only if and are incident with the same vertex in .
Which of the following statements is/are TRUE?
- (P) The line graph of a cycle is a cycle.
- (Q) The line graph of a clique is a clique.
- (R) The line graph of a planar graph is planar.
- (S) The line graph of a tree is a tree.
View worked solution
Answer: A
To determine which statements are true, let us analyze each one with definitions and counterexamples:
-
Statement (P): The line graph of a cycle is a cycle.
Let () be a cycle. Each edge in is incident to exactly two other edges (one at each endpoint). In the line graph , each vertex represents an edge of and has a degree of exactly . Since is connected, is also connected and forms a cycle of length ().
Thus, (P) is TRUE. -
Statement (Q): The line graph of a clique is a clique.
Let (a clique of size 4). Consider two independent (disjoint) edges in , such as and . Since and do not share any vertex, their corresponding vertices in are not connected by an edge. Thus, is not a complete graph (clique).
Thus, (Q) is FALSE. -
Statement (R): The line graph of a planar graph is planar.
Let (a star graph with leaves), which is a tree and therefore planar. All edges of share the single central vertex, meaning every pair of edges is mutually incident. Consequently, the line graph is the complete graph . By Kuratowski's Theorem, is non-planar.
Thus, (R) is FALSE. -
Statement (S): The line graph of a tree is a tree.
Let (a star graph with leaves), which is a tree. Since all edges share the central vertex, they are mutually incident. The line graph is (a cycle of length 3), which contains a cycle and is therefore not a tree.
Thus, (S) is FALSE.
Therefore, only statement P is TRUE.
Free practice · Your answers on this page are not saved.
