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Answer: 52
In a tree, the order () is defined as the maximum number of pointers an internal node can contain. An internal node with order contains at most block pointers and search keys.
To fit within a single disk block, the total size of these pointers and keys must not exceed the block size ():
Given:
- Block size () = bytes
- Search-key size () = bytes
- Pointer size () = bytes
Substituting these values into the inequality:
Thus, the maximum order of the tree is 52.
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