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GATE CS 2004 Q19 — Number Representations (Fixed and Floating Point)

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If 73x73_x (in base-x number system) is equal to 54y54_y (in base yy-number system), the possible values of xx and yy are

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Answer: D

To find the possible values of xx and yy, we first convert both numbers from their respective bases to base-10:

(73)x=7x1+3x0=7x+3(73)_x = 7x^1 + 3x^0 = 7x + 3 (54)y=5y1+4y0=5y+4(54)_y = 5y^1 + 4y^0 = 5y + 4

Since (73)x=(54)y(73)_x = (54)_y, we equate the two expressions:

7x+3=5y+4  ⟹  7x−5y=17x + 3 = 5y + 4 \implies 7x - 5y = 1

Additionally, we must satisfy the base constraints for the digits present in each number:

  • For (73)x(73)_x to be valid, the base xx must be strictly greater than the largest digit in the number, so x>7x > 7.
  • For (54)y(54)_y to be valid, the base yy must be strictly greater than the largest digit in the number, so y>5y > 5.

Now, let's test the given options against the equation 7x−5y=17x - 5y = 1:

  • Option A: x=8,y=16x = 8, y = 16
    7(8)−5(16)=56−80=−24≠17(8) - 5(16) = 56 - 80 = -24 \neq 1
  • Option B: x=10,y=12x = 10, y = 12
    7(10)−5(12)=70−60=10≠17(10) - 5(12) = 70 - 60 = 10 \neq 1
  • Option C: x=9,y=13x = 9, y = 13
    7(9)−5(13)=63−65=−2≠17(9) - 5(13) = 63 - 65 = -2 \neq 1
  • Option D: x=8,y=11x = 8, y = 11
    7(8)−5(11)=56−55=17(8) - 5(11) = 56 - 55 = 1 (This satisfies the equation, and both x>7x > 7 and y>5y > 5 hold true).

Thus, the correct option is D.

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